Resistance
AS UNIT 2Electricity and light2.2 ResistanceLearners should be able to demonstrate and apply their knowledge and understanding of: |
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|---|---|
| a) | The definition of potential difference |
| b) | The idea that potential difference is measured in volts (V) where [math]V = J C^{-1}[/math] |
| c) | The characteristics of [math] I – V[/math] graphs for the filament of a lamp, and a metal wire at constant temperature |
| d) | Ohm’s law, the equation [math][/math] and the definition of resistance |
| e) | Resistance being measured in ohms (Ω), where [math]Ω = VA^{-1}[/math] |
| f) | The application of [math] P = IV = I^2 R = \frac{V^2}{R}[/math] |
| g) | Collisions between free electrons and ions gives rise to electrical resistance, and electrical resistance increases with temperature |
| h) | The application of [math]R = \frac{\rho l}{A}[/math] the equation for resistivity |
| i) | The idea that the resistance of metals varies almost linearly with temperature over a wide range |
| j) | The idea that ordinarily, collisions between free electrons and ions in metals increase the random vibration energy of the ions, so the temperature of the metal increases |
| k) | What is meant by superconductivity, and superconducting transition temperature |
| l) | The fact that most metals show superconductivity, and have transition temperatures a few degrees above absolute zero ([math]-273℃[/math]//0 |
| m) | Certain materials (high temperature superconductors) having transition temperatures above the boiling point of nitrogen ([math]-196℃[/math]) |
| n) | Some uses of superconductors for example, MRI scanners and particle accelerators |
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Specified Practical Work o Investigation of the [math] I – V[/math] characteristics of the filament of a lamp and a metal wire at constant temperature o Determination of resistivity of a metal o Investigation of the variation of resistance with temperature for a metal wire |
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a) Definition of Potential Difference
- ⇒ Potential Difference:
- Potential Difference (p.d.) is defined as the amount of energy transferred per unit charge as the charge moves between two points in an electric circuit.
- It measures how much electrical energy is converted into other forms of energy (e.g., heat, light, etc.) when a charge flows through a component.
- [math]V = \frac{W}{Q}[/math]
- OR
- [math]V = \frac{E}{Q}[/math]
- Where:
- – V: Potential difference (measured in volts, V),
- – W(E): Work done or energy transferred (measured in joules, J)
- – Q: Electric charge (measured in coulombs, C).

- Figure 1 Potential Difference
-
b) Potential Difference Measured in Volts (V)
- The volt (V) is the SI unit of potential difference.
- ⇒ Definition:
- One volt is the potential difference between two points in a circuit when one joule of energy is transferred per one coulomb of charge.
- – In mathematical terms:
- [math]1V = 1J/C[/math]
- ⇒ Interpretation:
- If a potential difference of 5 V exists across a component, this means 5 J of energy is transferred per coulomb of charge passing through it.
-
c) Characteristics of I-V Graphs
- 1. Filament Lamp
- Shape of Graph:
- The I-V graph for a filament lamp is non-linear, resembling an S-shape.
- ⇒ Explanation:
- At low currents, the filament behaves like a simple resistor, and the current (I) increases linearly with voltage (V).
- As the current increases, the filament’s temperature rises due to electrical resistance.
- The resistance of the filament increases with temperature because the increased vibration of the metal ions impedes the flow of electrons.
- This results in a reduced rate of current increase at higher voltages, causing the graph to curve.

- Figure 2 I-V graph of filament
- 2. Metal Wire at Constant Temperature
- Shape of Graph:
- The I-V graph for a metal wire at constant temperature is a straight line through the origin.
- ⇒ Explanation:
- The resistance of the metal wire remains constant as long as the temperature does not change.
- This implies that the current (I) is directly proportional to the voltage (V), consistent with Ohm’s Law.
- Slope of the line represents [math]1/R[/math], where R is the resistance.

- Figure 3 I-V graph of Metal wire
-
d) Ohm’s Law
- ⇒ Definition:
- Ohm’s Law states that the current (I) flowing through a conductor is directly proportional to the potential difference (V) across it, provided the temperature and other physical conditions remain constant.
- Mathematically:
- [math]V = IR[/math]
- Where:
- – V: Potential difference (volts),
- – I: Current (amperes),
- – R: Resistance (ohms, Ω).
- ⇒ Resistance
- Definition:
- – Resistance (R) is a measure of how much a material opposes the flow of electric current.
- – It depends on the material, length, cross-sectional area, and temperature of the conductor.
- Unit:
- – The unit of resistance is the ohm (Ω), where:
- [math]1Ω = \frac{1V}{1A}[/math]
- Rearranging Ohm’s Law:
- [math]R = \frac{V}{I}[/math]
- ⇒ Practical Applications:
- 1. Filament Lamp:
- – Used in lighting.
- – As resistance increases with temperature, the lamp’s power output stabilizes at higher currents.
- 2. Metal Wires:
- – Metals with constant resistance are ideal for electrical wiring and creating stable circuits.
- 3. Ohm’s Law:
- – Crucial for analyzing circuits.
- – Used to calculate unknown quantities (voltage, current, or resistance).
- ⇒ Example Calculations
- 1. Calculating Current Using Ohm’s Law
- If the resistance of a resistor is R=10 Ω and the voltage across it is V=5 V, the current is:
- [math]\begin{gather}
I = \frac{V}{R} \\
I = \frac{5}{10} \\
I = 0.5 \text{ A}
\end{gather}[/math] - 2. Resistance from a Filament Lamp
- If a filament lamp draws I=0.4 A when connected to a 6 V supply:
- [math]\begin{gather}
R = \frac{V}{I} \\
R = \frac{6}{0.4} \\
R = 15 \,\Omega
\end{gather}[/math] - 3. Work Done by a Current
- If Q=3 C of charge moves through a component with a potential difference of V=2 V, the work done (W) is:
- [math]\begin{gather}
W = VQ \\
W = 2 \cdot 3 \\
W = 6 \text{ J}
\end{gather}[/math] -
e) Resistance and its Measurement
- ⇒ Definition of Resistance:
- Resistance (R) is a measure of how much a material opposes the flow of electric current.
- It depends on the material’s properties, dimensions, and temperature.
- ⇒ Unit of Resistance:
- Resistance is measured in ohms (Ω).
- One ohm is defined as the resistance when a potential difference of 1 volt drives a current of 1 ampere through a component.
- Mathematically:
- [math]1Ω = 1V/A[/math]
-
f) Electrical Power and its Relationship with Resistance
- ⇒ Electrical Power (P):
- Power is the rate at which electrical energy is transferred or converted in a circuit.
- Power depends on the current, voltage, and resistance of the circuit.

- Figure 4 Relationship between electric power and resistance
- ⇒ Equations for Power:
- 1. From basic definitions:
- [math]P = IV[/math]
- Where:
- – P: Power (in watts, W),
- – I: Current (in amperes, A),
- – V: Voltage (in volts, V).
- 2. Using Ohm’s Law ([math]V = IR[/math] ), alternative forms of the power equation are derived:
- – Substituting
- [math]\begin{gather} V = IR \quad \text{into} \quad P = IV \\
P = I^2 R \end{gather}[/math] - (Useful when current and resistance are known.)
- – Substituting
- [math]I = \frac{V}{R} [/math]
- into
- [math]\begin{gather}
P = IV \\
P = \frac{V^2}{R}
\end{gather}
[/math] - (Useful when voltage and resistance are known.)
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g) Resistance and Temperature
- ⇒ Origin of Electrical Resistance:
- Resistance arises due to collisions between free electrons and ions in a conductor.
- In metals:
- Free electrons flow when a potential difference is applied.
- The fixed ions in the lattice vibrate and scatter the moving electrons, impeding their motion.
- This scattering increases with temperature as the ions vibrate more vigorously, increasing resistance.
- ⇒ Temperature Dependence:
- In metals:
- Resistance increases with temperature because more collisions occur as the ion vibrations intensify.
- In semiconductors:
- Resistance decreases with temperature because more charge carriers are generated.
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e) Resistivity and the Resistivity Equation
- ⇒ Resistivity:
- Resistivity (ρ) is a material property that quantifies how strongly a material opposes the flow of electric current.
- It is a fundamental characteristic of a material, independent of its shape or size.
- Equation for Resistance in Terms of Resistivity:
- [math]R = ρ \frac{l}{A}[/math]
- Where:
- – R: Resistance (in ohms, Ω),
- – ρ: Resistivity (in ohm-meters, [math][/math]),
- – l: Length of the conductor (in meters, m),
- – A: Cross-sectional area of the conductor (in square meters, m2).
- ⇒ Understanding the Resistivity Equation
- 1. Dependence on Length (l):
- Resistance is directly proportional to the length of the conductor:
- [math]R ∝ l[/math]
- – A longer conductor provides more opportunity for electrons to collide with ions, increasing resistance.
- 2. Dependence on Cross-sectional Area (AAA):
- Resistance is inversely proportional to the cross-sectional area of the conductor:
- [math]R ∝ \frac{1}{A}[/math]
- – A larger cross-sectional area allows more electrons to flow simultaneously, reducing resistance.
- 3. Dependence on Material (ρ):
- – Materials with lower resistivity (e.g., copper, silver) are better conductors.
- – Materials with higher resistivity (e.g., rubber, glass) are insulators.
- ⇒ Key Applications of the Resistivity Equation
- 1. Designing Conductors:
- Wires are made from materials with low resistivity (e.g., copper) to minimize energy loss.
- 2. Determining Wire Dimensions:
- To reduce resistance in high-power circuits, wires are designed to be short and thick.
- 3. Material Characterization:
- Resistivity helps identify the suitability of materials for specific applications (e.g., metals for conductors, ceramics for insulators).
- ⇒ Example Calculations
- 1. Calculating Resistance Using Resistivity:
- A copper wire ([math]ρ = 1.7 × 10^{-8} Ωm[/math] ) has a length [math]l = 2m[/math] and cross-sectional area [math]A = 1 × 10^{-6} m^2[/math]. Find its resistance.
- [math]\begin{gather}
R = \frac{\rho l}{A} \\
R = \frac{(1.7 \times 10^{-8}) \times 2}{1 \times 10^{-6}} \\
R = 3.4 \times 10^{-2} \,\Omega
\end{gather}[/math] - 2. Calculating Power Dissipated:
- A resistor with [math]R = 10 Ω[/math] carries a current of [math]l =2m[/math]. Find the power dissipated.
- [math]\begin{gather}
P = I^2 R \\
P = (2)^2 \times 10 \\
P = 40 \text{ W}
\end{gather}[/math] -
i) Resistance of Metals and Temperature Dependence
- ⇒ Relationship Between Resistance and Temperature in Metals
- The resistance (R) of metals generally increases linearly with temperature over a wide range.
- This is because, as temperature rises, the metal ions in the lattice vibrate more intensely, increasing the probability of collisions between free electrons and ions.
- ⇒ Mathematical Relationship:
- The resistance R of a metal at a temperature T can be expressed as:
- [math]R_T = R_0 (1 + αΔT)[/math]
- Where:
- – [math]R_T[/math]: Resistance at temperature T,
- – [math]R_o[/math] : Resistance at a reference temperature (usually [math][/math] or room temperature),
- – α: Temperature coefficient of resistance (a material-dependent constant),
- [math]ΔT = T – T_0[/math]: Change in temperature.

- Figure 5 Temperature and resistivity
- ⇒ Characteristics:
- 1. At low temperatures, the resistance of most metals approaches a minimum value, as thermal vibrations reduce.
- 2. At higher temperatures, the relationship between resistance and temperature becomes less linear.
-
j) Collisions Between Free Electrons and Ions in Metals
- ⇒ Resistance Increases Temperature
- Mechanism:
- – In a metal, free electrons flow when a potential difference is applied, creating an electric current
- – As these electrons move, they collide with the metal ions in the lattice.
- – Each collision transfers energy from the electrons to the ions, causing the ions to vibrate more intensely.
- ⇒ Energy Transfer:
- The increased vibration energy of the ions results in a rise in the temperature of the metal.
- This process is responsible for the conversion of electrical energy into heat, which explains why conductors heat up when current flows through them.
- ⇒ Effects:
- 1. The greater the current (flow of electrons), the more frequent the collisions, leading to a higher temperature.
- 2. This is the basis of Joule heating in resistors and electric wires.
-
k) Superconductivity and Transition Temperature
- ⇒ Superconductivity:
- Superconductivity is a phenomenon in which a material’s electrical resistance drops to exactly zero when it is cooled below a certain critical temperature, known as the superconducting transition temperature (TC).
- ⇒ Properties of Superconductors:
- 1. Zero Electrical Resistance:
- When a material becomes superconducting, it can conduct electricity without any energy loss.
- Electrons form Cooper pairs, which move without scattering.
- 2. Expulsion of Magnetic Fields (Meissner Effect):
- Superconductors expel all internal magnetic fields, causing magnetic field lines to bend around the material.
- ⇒ Superconducting Transition Temperature (TC):
- The critical temperature (TC) is the temperature below which a material becomes superconducting.
- ⇒ For many materials:
- – TC is typically very low (e.g., 4.2 K for mercury).
- – High-temperature superconductors, like certain ceramic compounds, can have TC>77K, making them practical for some applications.
- ⇒ Superconductivity
- Superconductivity arises from the formation of Cooper pairs of electrons:
- – These pairs experience an attractive interaction mediated by lattice vibrations (phonons).
- – The pairs move through the lattice without resistance because they are not scattered by the ions.
- ⇒ Applications of Superconductivity
- 1. Magnetic Levitation (Maglev Trains):
- Superconductors are used to create strong magnetic fields for levitation and propulsion.
- 2. MRI Machines:
- Superconducting magnets are used in medical imaging to generate powerful, stable magnetic fields.

- Figure 6 MRI for Brain
- 3. Particle Accelerators:
- Superconducting magnets guide particles at extremely high speeds.
- 4. Lossless Power Transmission:
- Superconducting cables can transmit electricity without energy loss.
-
l) Superconductivity in Metals and Materials
- ⇒ Most Metals and Superconductivity
- Many metals exhibit superconductivity, meaning they transition to a state of zero electrical resistance below a specific critical temperature, called the superconducting transition temperature (TC).
- For most pure metals:
- – TC is typically only a few degrees above absolute zero (-273℃).
- Example:
- – Mercury (TC =2K),
- – Lead (TC =2K),
- – Tin (TC =7K).
-
m) High-Temperature Superconductors
- High-temperature superconductors are materials that become superconducting at higher temperatures, significantly above the transition temperatures of metals.
- Examples include certain ceramic compounds like:
- – Yttrium barium copper oxide (YBCO) with TC >90K
- – Bismuth strontium calcium copper oxide (BSCCO).
- ⇒ Transition Temperature and Nitrogen Boiling Point:
- The boiling point of liquid nitrogen is (-196 , (77K)).
- High-temperature superconductors with TC >77K are practical because they can operate using liquid nitrogen as a coolant, which is much cheaper and more accessible than liquid helium (used for lower TC).
-
n) Applications of Superconductors
- 1. Magnetic Resonance Imaging (MRI) Scanners
- ⇒ Purpose:
- MRI scanners use superconducting magnets to produce powerful, stable magnetic fields.
- These fields align the protons in the human body, and the signals emitted as they return to their original states are used to create detailed images of tissues.
- ⇒ Why Superconductors?:
- i) Superconducting magnets generate stronger magnetic fields with high efficiency, enabling clearer imaging.
- ii) They consume significantly less energy due to the zero-resistance property.
- 2. Particle Accelerators
- Purpose:
- – Particle accelerators, such as the Large Hadron Collider (LHC), accelerate particles to near the speed of light for research in high-energy physics.
- Role of Superconductors:
- – Superconducting magnets guide and focus the particle beams within the accelerator by generating ultra-strong magnetic fields.
- – Superconducting materials ensure energy efficiency and reduce operational costs.
- 3. Maglev (Magnetic Levitation) Trains
- Functionality:
- Superconducting magnets levitate the train above the tracks, reducing friction and allowing high speeds.
- Benefits:
- High efficiency, smooth motion, and reduced energy consumption.
- Example:
- Japan’s maglev trains use superconducting magnets to reach speeds of over 500 km/h.
- 4. Electric Power Transmission
- Superconducting cables can transmit electricity without energy loss due to resistance.
- Benefits:
- High efficiency in power distribution, particularly in large grids.
- 5. Other Applications
- SQUIDs (Superconducting Quantum Interference Devices):
- Extremely sensitive magnetic field detectors used in research and medical diagnostics.
- Fusion Reactors:
- Superconductors are used to confine plasma in reactors like ITER (International Thermonuclear Experimental Reactor).
- ⇒ Advantages of High-Temperature Superconductors
- 1. Cost-Effective Cooling:
- Liquid nitrogen (-196℃) is cheaper and easier to handle than liquid helium (-269℃).
- 2. Wider Range of Applications:
- High TC materials make superconductors more feasible for large-scale, real-world applications.
- ⇒ Challenges in Superconductivity
- 1. Material Limitations:
- Many high-temperature superconductors are brittle ceramics, difficult to manufacture and shape.
- 2. Cooling Requirements:
- Even high-temperature superconductors require cooling to cryogenic temperatures, limiting their use in everyday applications.
- 3. Magnetic Field Effects:
- Superconductivity can be disrupted by strong external magnetic fields (critical field strength).
-
Specified Practical Work
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1. Investigation of the I-V Characteristics of the Filament of a Lamp and a Metal Wire at Constant Temperature
- ⇒ Aim:
- To investigate the relationship between current (I) and potential difference (V) for:
- A filament lamp.
- A metal wire at constant temperature.

- Figure 7 Investigation of the I-V graph
- ⇒ Apparatus:
- DC Power Supply.
- Ammeter (to measure current, I).
- Voltmeter (to measure potential difference, V).
- Filament lamp.
- Metal wire (e.g., copper wire).
- Variable resistor (or rheostat) to vary current.
- Connecting wires.
- ⇒ Procedure:
- 1. Set up the circuit:
- Connect the filament lamp or metal wire in series with the power supply, ammeter, and variable resistor.
- Connect the voltmeter across the lamp or wire to measure V.
- 2. Measure the I-V Characteristics:
- Gradually increase the supply voltage using the variable resistor or adjust the power supply.
- Record the corresponding values of current (I) and voltage (V) for each setting.
- 3. For the Metal Wire:
- Ensure the temperature of the metal wire remains constant by using small currents to avoid heating. Allow time between measurements for cooling.
- 4. For the Filament Lamp:
- Repeat the process but note the lamp’s resistance increases as it heats up due to the increase in filament temperature.
- 5. Plot Graphs:
- Plot I (current) on the y-axis and V (voltage) on the x-axis.
- ⇒ Observations and Results:
- Metal Wire:
- – The graph will be a straight line, showing a linear relationship between I and V, following Ohm’s Law ( [math]V = IR[/math]).
- Filament Lamp:
- – The graph will initially be straight but will curve as V increases, indicating that resistance increases with temperature due to the filament heating up.
- ⇒ Conclusion:
- Metal wire: Resistance is constant and follows Ohm’s Law.
- Filament lamp: Resistance increases as the temperature of the filament increases, causing the I−V graph to curve.
-
2. Determination of Resistivity of a Metal
- ⇒ Aim:
- To determine the resistivity (ρ) of a given metal wire.

- Figure 8 Determination of resistivity of a metal
- ⇒ Apparatus:
- Metal wire of known material.
- DC Power Supply.
- Micrometer Screw Gauge (to measure the diameter of the wire).
- Ruler (to measure the length of the wire).
- Ammeter.
- Voltmeter.
- Variable resistor.
- Connecting wires.
- ⇒ Procedure:
- 1. Measure the Dimensions of the Wire:
- Use the micrometer screw gauge to measure the diameter of the wire (d) at several points and calculate the average.
- Calculate the cross-sectional area:
- [math]\begin{gather}
A = \frac{\pi d^2}{4}
\end{gather}[/math] - Measure the length (L) of the wire using a ruler.
- 2. Set Up the Circuit:
- Connect the metal wire in series with the power supply, ammeter, and variable resistor.
- Connect the voltmeter across the wire.
- 3. Measure Current and Voltage:
- Gradually increase the voltage using the variable resistor.
- Record the corresponding current (I) and voltage (V) for multiple settings.
- 4. Calculate Resistance (R):
- For each pair of I and V, calculate resistance using:
- [math]\begin{gather}
R = \frac{V}{I}
\end{gather}[/math] - 5. Determine Resistivity (ρ):
- Using the formula:
- [math]\begin{gather}
\rho = \frac{R A}{L}
\end{gather}[/math] - Substitute the values of R, A, and L to calculate resistivity.
- ⇒ Precautions:
- Use low currents to avoid heating the wire, which would change its resistance.
- Take multiple readings of d, L, I, and V to minimize errors.
-
3. Investigation of the Variation of Resistance with Temperature for a Metal Wire
- ⇒ Aim:
- To investigate how the resistance of a metal wire changes with temperature.

- Figure 9 Investigation of the variation of Resistance with temperature
- ⇒ Apparatus:
- Metal wire (e.g., nichrome or copper).
- DC power supply.
- Ammeter and Voltmeter.
- Rheostat.
- Water bath or oil bath (to heat the wire).
- Thermometer.
- Beaker and heater.
- Connecting wires.
- ⇒ Procedure:
- 1. Set Up the Wire in a Water Bath:
- Submerge the metal wire in a water bath or oil bath, ensuring good thermal contact.
- 2. Measure Resistance at Different Temperatures:
- Gradually heat the bath using a heater.
- Measure the temperature (T) using the thermometer.
- For each temperature, measure the current (I) and voltage (V) and calculate resistance using:
- [math]\begin{gather}
R = \frac{V}{I}
\end{gather}[/math] - 3. Record Data:
- Record R at several temperature points as the bath heats up.
- 4. Plot a Graph:
- Plot R (resistance) on the y-axis and T (temperature) on the x-axis.
- ⇒ Observations:
- Metal Wire:
- – Resistance increases almost linearly with temperature.
- – This is due to increased collisions between free electrons and vibrating metal ions.
- ⇒ Conclusion:
- Resistance of a metal wire increases with temperature due to increased lattice vibrations.
- The graph can be used to calculate the temperature coefficient of resistance (α) using the relation:
- [math]\begin{gather}
R_T = R_0 (1 + \alpha \Delta T)
\end{gather}[/math]