AS UNIT 2

Electricity and light

2.1 Conduction of electricity

Learners should be able to demonstrate and apply their knowledge and understanding of:

a) The fact that the unit of charge is the coulomb (C), and that an electron’s charge, e, is a very small fraction of a coulomb
b) The fact that charge can flow through certain materials, called conductors
c) Electric current being the rate of flow of charge
d) The use of the equation [math]I = \frac{∆Q}{∆t}[/math]
e) Current being measured in amperes (A), where [math]A = C s^{-1}[/math]
f) The mechanism of conduction in metals as the drift of free electrons
g) The derivation and use of the equation [math]I = nAve[/math]  for free electrons
  • (a) The Unit of Charge and the Electron’s Charge

  • The Coulomb (C) as the Unit of Charge
  • The coulomb (C) is the standard SI unit of electric charge.
  • It is defined as the amount of charge that flows through a conductor carrying a steady current of 1 ampere in 1 second:
  • [math]1C = 1A . 1s[/math]
  • – Here, ampere (A) is the unit of electric current, and second (s) is the unit of time.
  • A charge of 1 coulomb represents a significant quantity of electric charge.
  • ⇒  Charge of an Electron (e)
  • The elementary charge, denoted as e, is the magnitude of the electric charge carried by a single electron or proton:
  • [math]e = 1.602 × 10^{-19} C[/math]
  • Electrons have a charge of −e, while protons have a charge of +e.
  • Figure 1 Electric Charges
  • Since e is a very small fraction of a coulomb, a single electron or proton carries an almost negligible amount of charge.
  • ⇒  Number of Electrons in 1 Coulomb
  • Because the charge of one electron is so small, it takes a very large number of electrons to make up 1 coulomb of charge:
  • [math]\begin{gather}
    \text{Number of electrons} = \frac{1 \text{ C}}{1.602 \times 10^{-19} \text{ C/electron}} \\
    \text{Number of electrons} \approx 6.242 \times 10^{18} \text{ electrons}
    \end{gather}[/math]
  • This illustrates that the coulomb represents a macroscopic (large-scale) quantity of charge.
  • ⇒  Comparison of Coulomb and Elementary Charge
  • The charge of everyday objects is typically measured in coulombs because the elementary charge (e) is too small to describe macroscopic amounts of charge.
  • For instance:
  • – A 1 ampere current flowing for 1 second moves approximately [math]6.242 × 10^{18}[/math]
  • (b) Charge Flow Through Conductors

  • ⇒  Conductors
  • Conductors are materials that allow electric charge to flow through them easily.
  • This property arises from the structure of the material, where certain electrons (called free electrons) are not tightly bound to their atoms and can move freely.
  • Figure 2 Flow of electric Charges
  • ⇒  How Charge Flows in Conductors
  • 1. Free Electrons in Conductors:
  • Metals such as copper, silver, and aluminum are excellent conductors because their outermost electrons (valence electrons) are loosely held by their nuclei.
  • These free electrons form an “electron cloud” or “sea of electrons” that can move through the material when a potential difference (voltage) is applied.
  • 2. Electric Field and Current:
  • When a conductor is connected to a voltage source (e.g., a battery), an electric field is established inside the material.
  • This field exerts a force on the free electrons, causing them to drift in the direction opposite to the electric field. This motion of electrons constitutes an electric current.
  • 3. Charge Carriers:
  • In metals, electrons are the primary charge carriers.
  • In electrolytes (e.g., saltwater), ions (positive and negative) carry the charge.
  • ⇒  Examples of Conductors
  • Metals: Copper, silver, gold, and aluminum are common electrical conductors.
  • Example: Copper is widely used in electrical wiring due to its low resistance and high conductivity.
  • Graphite: A non-metal that conducts electricity because of the mobility of its delocalized electrons.
  • ⇒ Ionic Solutions (Electrolytes):
  • Salt dissolved in water allows ions to move freely, enabling the flow of charge.
  • Insulators
  • Insulators are materials in which electrons are tightly bound to their atoms and cannot move freely. Examples include rubber, glass, and plastic.
  • In insulators, there are no free charge carriers to support the flow of electric charge.
  • c) Electric Current as the Rate of Flow of Charge

  • ⇒  Definition of Electric Current
  • Electric current (I) is defined as the rate at which electric charge (Q) flows through a conductor or a circuit.
  • Mathematically, it is expressed as:
  • [math]\begin{gather}
    I = \frac{\Delta Q}{\Delta t} \\
    I = \frac{5 \text{ C}}{10 \text{ s}} \\
    I = 0.5 \text{ A}
    \end{gather}[/math]
  • Where:
  • – I: Electric current (measured in amperes, A).
  • – ΔQ: Total electric charge that flows through a point (measured in coulombs, C),
  • – Δt: Time during which the charge flows (measured in seconds, s).
  • ⇒  Units of Electric Current
  • The ampere (A) is the SI unit of electric current.
  • It is defined as:
  • [math]1A = 1 C/s[/math]
  • This means a current of 1 ampere corresponds to 1 coulomb of charge flowing past a given point in 1 second.
  • ⇒  Understanding Current
  • Positive and Negative Charges:
  • – By convention, the direction of current is the flow of positive charge. In most cases, however, current in a metal is due to the movement of electrons, which flow in the direction opposite to the conventional current.
  • Steady Current:
  • – If the charge flow is constant over time, the current is said to be steady, and the equation simplifies to:
  • [math]I = \frac{Q}{t}[/math]

  • d) Application of the Equation [math]I = \frac{\Delta Q}{\Delta t}[/math]

  • Example 1: Calculating Current
  • – If 5 C of charge flows through a circuit in 10 s, the current is:
  • [math]\begin{gather}
    I = \frac{\Delta Q}{\Delta t} \\
    I = \frac{5 \text{ C}}{10 \text{ s}} \\
    I = 0.5 \text{ A}
    \end{gather}[/math]
  • – This means a current of [math][/math] is flowing through the circuit.
  • Example 2: Determining Charge
  • – Rearranging the equation:
  • [math]\Delta Q = I \cdot \Delta t[/math]
  • – If a current of 2 A flows for 4 s, the total charge transferred is:
  • [math]\begin{gather}
    \Delta Q = I \cdot \Delta t \\
    \Delta Q = (2)(4) \\
    \Delta Q = 8 \text{ C}
    \end{gather}[/math]
  • Example 3: Real-Life Scenario
  • – In a smartphone battery, suppose 2 A flows while charging for 3000 s (50 minutes).
  • – The total charge delivered is:
  • [math]\begin{gather}
    \Delta Q = I \cdot \Delta t \\
    \Delta Q = (1.2)(3000) \\
    \Delta Q = 3600 \text{ C}
    \end{gather}[/math]
  • 1. Physical Meaning:
  • Current measures how quickly charge is flowing in a circuit.
  • A higher current means more charge is passing through a point in the circuit per unit time.
  • 2. Direction of Current:
  • Conventional current flows from the positive terminal to the negative terminal of a power source.
  • In reality, electrons (negative charges) flow in the opposite direction.
  • 3. Steady and Time-Varying Current:
  • For steady currents, the equation [math]I = \frac{\Delta Q}{\Delta t}[/math] is used directly.
  • For time-varying currents, more advanced calculus-based analysis is required.
  • e) Current Measured in Amperes (A)

  • Definition of Ampere
  • Electric current (I) is the rate of flow of electric charge (Q) over time (t):
  • [math]I = \frac{∆Q}{∆t}[/math]
  • The SI unit of electric current is the ampere (A), defined as:
  • [math]1A = 1C/s[/math]
  • This means a current of 1 ampere represents the flow of 1 coulomb of charge through a point in a conductor every second.
  • ⇒  Characteristics of Current Measurement
  • Conventional Current:
  • – By convention, current is the flow of positive charge. However, in most metallic conductors, current results from the movement of free electrons, which flow in the opposite direction to the conventional current.
  • Practical Units:
  • – Larger currents are often measured in amperes (A).
  • – Smaller currents can be expressed in:
  • Milliamperes (mA): [math]1 mA = 10^{-3} A[/math]
  • Microamperes (μA): [math]1 μA = 10^{-6} A[/math]
  • f) Mechanism of Conduction in Metals

  • ⇒  Structure of Metals:
  • Metals consist of a lattice of positive metal ions surrounded by a “sea” of free electrons.
  • These free electrons are loosely bound to their atoms and can move freely within the metal.
  • Figure 3 Metallic bonding
  • ⇒  Drift of Free Electrons
  • 1. Random Motion:
  • In the absence of an electric field, free electrons move randomly within the metal.
  • There is no net flow of charge because the random motions cancel out.


    Figure 4 Drift Velocity

  • 2. Electric Field:
  • When a potential difference (voltage) is applied across the metal, an electric field is created.
  • The electric field exerts a force on the free electrons, causing them to drift in the direction opposite to the field (since electrons are negatively charged).
  • This drift motion of electrons constitutes the electric current in the metal.
  • Figure 5 Electric Field
  • ⇒  Drift Velocity (v):
  • The drift velocity is the average velocity of electrons as they move under the influence of the electric field.
  • It is typically very small (on the order of [math]10^{-4}[/math]m/s) because electrons collide frequently with the metal ions, slowing their progress.
  • g)    Derivation and Use of the Equation [math]I = nAve[/math]

  • The equation [math]I = nAve[/math] provides a relationship between the macroscopic current (I) and the microscopic properties of the conductor.
  • ⇒  Parameters in the Equation
  • – I: Electric current (A),
  • – n: Number density of free electrons (electrons per unit volume, measured in [math]m^{-3}[/math]),
  • – A: Cross-sectional area of the conductor ( [math]m^2[/math]),
  • – v: Drift velocity of the electrons (m/s),
  • – e: Charge of an electron ( [math]1.602 × 10^{-19} C[/math]).
  • ⇒  Derivation of [math]I = nAve[/math]
  • 1. Electric Current:
  • Current is defined as the total charge passing through the cross-sectional area of the conductor per second:
  • [math]I = \frac{∆Q}{∆t}[/math]
  • 2. Charge Flow:
  • The total charge (Q) flowing through the conductor in time Δt is the product of:
  • – The number of electrons (N),
  • – The charge of each electron (e):
  • [math]Q = N . e[/math]
  • 3. Number of Electrons:
  • The total number of electrons passing through the cross-sectional area is:
  • [math]N = n ⋅ A ⋅ v ⋅ Δt[/math]
  •  Where:
  • – n: Number density of free electrons,
  • – A: Cross-sectional area of the conductor,
  • – v: Drift velocity,
  • – Δt: Time period.
  • 4. Substituting for Q:
  • [math]Q = n ⋅ A ⋅ v ⋅ Δt ⋅ e.[/math]
  • 5. Current (I):
  • Dividing by Δt to find the current:
  • [math]I = \frac{∆Q}{∆t} = n ⋅ A ⋅ v ⋅ Δt ⋅ e.[/math]
  • ⇒  Physical Meaning of the Equation
  • [math]I = nAve[/math] relates the macroscopic current (I) to the microscopic properties of the conductor:
  • – n: Determines how many free electrons are available to carry charge.
  • – A: The larger the cross-sectional area, the more electrons can pass through at once.
  • – v: The drift velocity of electrons is directly proportional to the current.
  • – e: The charge of each electron defines the contribution of each electron to the total current.
  • ⇒  Practical Applications of [math]I = nAve[/math]
  • 1. Calculating Drift Velocity:
  • If the current, number density, and conductor area are known, the drift velocity can be calculated:
  • [math]v = \frac{I}{nAe}[/math]
  • 2. Analyzing Conductors:
  • The equation can be used to compare the conductivity of different materials by considering their number density (n).
  • 3. Understanding Current Flow:
  • Provides insight into the microscopic processes that generate a macroscopic current in conductors.
  • ⇒  Example Calculation
  • A copper wire has a cross-sectional area of [math]A = 1 mm^2 = 1 × 10^{-6} m^2[/math], carries a current of [math]I = 3A[/math], and has a number density [math]n = 8.5 × 10^{28} m^{-3}[/math]. The drift velocity (v) can be calculated as:
  • [math]v = \frac{I}{n A e}[/math]
  • Substituting:
  • [math]\begin{gather}
    v = \frac{I}{n A e} \\
    v = \frac{3}{(8.5 \times 10^{28}) (1 \times 10^{-6}) (1.602 \times 10^{-19})} \\
    v \approx 2.2 \times 10^{-4} \text{ m/s}
    \end{gather}[/math]
  • The drift velocity is very small, which highlights that even small velocities can result in large currents due to the high number density of electrons in metals.
error: Content is protected !!