Sp Unit 4.1
Practicals
Capacitance
Sp Unit 4.1PracticalsCapacitanceLearners should be able to demonstrate and apply their knowledge and understanding of: |
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| 1. | Investigation of the charging and discharging of a capacitor to determine the time constant |
| 2. | Investigation of the energy stored in a capacitor |
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1. Investigation of the charging and discharging of a capacitor to determine the time constant
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⇒ Objective:
- To study the charging and discharging process of a capacitor in a RC circuit and determine its time constant (τ=RC).
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⇒ Apparatus Required:
- – A capacitor (e.g., 1000 µF)
- – A resistor (e.g., 10 kΩ)
- – A DC power supply (e.g., 9V battery)
- – A switch
- – A voltmeter (or oscilloscope)
- – A stopwatch
- – Connecting wires
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⇒ Theory:
- When a capacitor charges through a resistor, the voltage across it follows:
- [math]V = V_0 \left(1 – e^{-\frac{t}{RC}}\right)[/math]
- When it discharges, the voltage follows:
- [math]V = V_0 e^{-\frac{t}{RC}}[/math]
- Where:
- – [math]V_o[/math] = initial voltage
- – R = resistance (Ω)
- – C = capacitance (F)
- – t = time (s)
- – [math]τ = RC[/math] is the time constant, the time taken for the voltage to decrease to 37% of its initial value.
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⇒ Procedure:
- Charging Phase:
- Set up the circuit with the capacitor, resistor, power supply, and switch in series.
- Close the switch to allow current to flow and start the charging process.
- Record voltage readings across the capacitor every 5 seconds until it reaches close to the supply voltage.
- Plot a graph of V vs. t. The curve should show an exponential increase.

- Figure 1 Charging phase of capacitor
- Discharging Phase:
- Open the switch and remove the power supply.
- Record the voltage every 5 seconds as the capacitor discharges.
- Plot a graph of V vs. t. The curve should show an exponential decay.
- Determine the time constant (τ) by finding the time when voltage reaches 37% of [math]V_o[/math]

- Figure 2 Discharging phase of capacitor
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⇒ Results & Analysis:
- – The charging curve follows an exponential rise.
- – The discharging curve follows an exponential decay.
- – The time constant (τ) is determined from the decay curve.
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⇒ Precautions & Errors:
- – Use low-leakage capacitors for accuracy.
- – Ensure the resistor value is large enough to slow the process.
- – Use a digital voltmeter for precise readings.
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⇒ Conclusion:
- This experiment demonstrates that a capacitor charges and discharges exponentially. The time constant (τ) is the key parameter governing the process.
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2. Investigation Of the Energy Stored In A Capacitor
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⇒ Objective:
- To measure the energy stored in a capacitor and verify the formula:
- [math]E = \frac{1}{2} C V^2[/math]
- Where:
- – E = stored energy (J)
- – C = capacitance (F)
- – V = voltage (V)
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⇒ Apparatus Required:
- – A capacitor (e.g., 1000 µF)
- – A resistor (e.g., 1 kΩ)
- – A DC power supply (9V battery)
- – A switch
- – A voltmeter
- – A Joule meter or a method to measure power dissipation

- Figure 3 Energy stored in a capacitor
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⇒ Procedure:
- Charging Phase:
- Connect the circuit with the capacitor, resistor, power supply, and switch.
- Close the switch to start charging the capacitor.
- Measure the voltage across the capacitor at regular intervals.
- Use the formula [math]E = \frac{1}{2} C V^2[/math] to calculate the stored energy.
- Discharging Phase (Energy Transfer to a Load):
- Disconnect the power supply and connect the capacitor to a known resistor.
- Measure the current and voltage as the capacitor discharges.
- Calculate the power dissipated using [math]P = VI[/math] and integrate over time to find the energy released.
- Compare this with the theoretical energy stored ([math] \frac{1}{2} C V^2[/math] ).
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⇒ Results & Analysis:
- – The measured energy closely matches the theoretical energy.
- – Small differences may be due to resistance losses and capacitor inefficiencies.
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⇒ Precautions & Errors:
- – Ensure good connections to reduce resistance losses.
- – Use a high-precision voltmeter for accurate readings.
- – Minimize leakage current from the capacitor.
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⇒ Conclusion:
- This experiment confirms that the energy stored in a capacitor is given by [math]E = \frac{1}{2} C V^2[/math]. The energy transfer can be observed by discharging the capacitor through a resistor.